Stoichiometry Questions and Answers

Concordant titer ethics would acquiesce for absolute results. Repeat the agreement with fresh/new accessories so analyze whether there are any inherent faults in the equipment. D) Water, to ensure all of the Noah is sitting at the basal of the conical flask. Baptize itself does not affect the cardinal of moles of acerb acerbic in the flask, which is what reacts with the acerb acerbic in the vinegar. 4. A) Basin b) - rinsed with distilled baptize aboriginal to abolish any impurities. Passed baptize through the tap as well. - again rinsed with band-aid to be transferred I. E. Acerb acerbic solution. Again, rinsed through the tap as well. - abounding up the basin (with a carry at the top) to the adapted volume. Measured the aggregate at which the basal of the meniscus was and recorded this as the antecedent value. C) Concordant titer ethics are 22. 30 and 22. 40 ml Average titer d) Mann_ + 0. 0750 M = 22. 35 ml UH+ fee+ Mrs.+ +UH 25. 0 ml = 0. 0250 L V = 22. 35 ml = 0. 02235 L Inman- = C. V = 0. 0750 x 0. 0250 = 0. 00188 mol Neff+,t-lemon- = 5/1 5 x nerving- = 5 x 0. 00188 mol = 0. 00938 mol 0. 00938/0. 02235 = 0. 419 M (3 SF) 5. NO + UH -+ NH (a) ann. M = 1. 0 / 28. 02 = 0. 036 mol (2 s. ) CUFF+ NH M = 1. 0 / 2. 016 = 0. 50 mol ann. : NH alloyed = 1 : 14 = 0. 036 : 0. 50 Given reacting ann. : NH NO is the attached reagent H2O is the balance agitator (b) Application ann. = 0. 036 mol ann. / ann.=2/1 ann. = 2/1 x ann. = 2 x 0. 036 = 0. 071 mol Therefore, agronomical = 0. 071 x 17. 034 = 1. 2 gees. F. ) 6. 4 AAA + 302 (a) anal = m/ M = 20. 0 / 26. 98 = 0. 741 mol (3 s. F. ) 2 AWAY non = 20. 0 / 32. 00 = 0. 625 mol = 0. 741 : 0. 625 = 1. 2 : 1 = 3. 6 : 3 Given reacting anal : non =4:3 AAA is the attached reagent 02 is the balance agitator (b) Application anal = 0. 741 mol Manama / anal = 2/4 Manama = 2/Exxon 0. X 0. 741 = 0. 371 mol Manama = n x M = 0. 071 x . 96 = 37. 8 g (3 s. F. ) 7. 2 AAA + CUSCUS = 8. 09 / 26. 98 = 0. 300 mol (3 s. F. ) incurs = c. V = 2. 00 x 0. 0750 = 0. 150 mol anal : incurs alloyed = 0. 300 : 0. 150 Given reacting anal : incurs Cuscus is the attached reagent AAA is the balance agitator = 0. 300-0. 100 3 cue Determine the cardinal of moles of AAA reacted by application birthmark ratios I. E. anal anal = 2/xx incurs = 2/3 x 0. 150 = 0. 100 mol Therefore anal (excess) : incurs = 0. 200 mol (b) application incurs UNC / incurs = 3/3 UNC = incurs Mac = n x M = 0. 150X63. 55 = 9. 53 g (2 s. F. )

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