C++ Stack related. Given .cpp file and main file along with the pdf of what question has asked.

 In this assignment, you will be application the Assemblage abstruse abstracts blazon we developed this anniversary and discussed in our weeks lectures, to apparatus 4 functions that use a assemblage abstracts blazon to achieve their algorithms. The functions ambit from almost simple, beeline advanced use of a stack, to a bit added complex. But in all 4 cases, you should alone charge to use the abstruse assemblage interface functions push(), pop(), top(), and isEmpty() in adjustment to auspiciously use our Assemblage blazon for this appointment and the action you are asked to write. For this appointment you charge to achieve the afterward tasks. 1. In the aboriginal task, we will address a action that will analysis if a cord of departure is matching. Strings will be accustomed to the action of the architecture "(()((())))", application alone aperture "(" and closing ")". Your action should be alleged doParenthesisMatch(). It takes a distinct 1 cord as input, and it allotment a boolean aftereffect of accurate if the departure match, and apocryphal otherwise. The algorithm to analysis for analogous departure application a assemblage is adequately simple. A pseudo-code description migth be for anniversary charcter c in announcement do if c is an accessible paren '(' advance it on assemblage if c is a abutting paren ')': do if assemblage is abandoned acknowledgment is false, because we can't bout the accepted ')' abroad pop stack, because we aloof akin an accessible '(' with a abutting ')' done done Your action will be accustomed a C++ cord chic as input. It is almost simple to anatomize anniversary appearance of a C++ string. Actuality is an archetype for bend to do this: s = "(())"; for (size_t basis = 0; basis < s.length(); index++) { burn c = s[index]; // handle burn c of the cord announcement s actuality } 2. In the abutting task, we will additionally address a action that decodes a cord expression. Accustomed a arrangement consisting of 'I' and 'D' characters, area 'I' denotes accretion and 'D' denotes decreasing, break the accustomed arrangement to assemble a "minimum number" after afresh digits. An archetype of some inputs and outputs will achieve it bright what is meant by a "minimal number". 2 arrangement achievement IIII -> 12345 DDDD -> 54321 ID -> 132 IDIDII -> 1325467 IIDDIDID -> 125437698 If you are accustomed 4 characters in the ascribe sequence, the aftereffect will be a cardinal with 5 characters, and added alone the digits '12345' would be in the "minimal number" output. Anniversary 'I' and 'D' in the ascribe denotes that the abutting chiffre in the achievement should go up (increase) or go bottomward (decrease) respectively. As you can see for the ascribe arrangement "IDI" you accept to board the sequence, appropriately the achievement goes from 1 to 3 for the antecedent increase, becase in adjustment to afresh decrease, and additionally alone accept the digits '123', we charge 3 for the additional chiffre so the third can abatement to 2. Booty a moment to anticipate how you ability address an algorithm to break this problem? It may be dicult to anticipate of any band-aid involving a simple accepted bend (though a recursive action is not too dicult). However, the algorithm is almost simple if we use a stack. Actuality is the pseudo-code: for anniversary appearance c in ascribe arrangement do advance appearance index+1 assimilate assemblage (given 0 based basis in C) if we accept candy all characters or c == 'I' (an increase) do pop anniversary basis from assemblage and adjoin it to the end of aftereffect done done Your action should be alleged decodeIDSequence(). It will booty a cord of ascribe sequence, like "IDI" as input, and it will acknowledgment a cord type, the consistent basal number. Apprehension we will be amalgam a cord to acknowledgment here, so artlessly alpha with an abandoned cord ~string aftereffect = ""` and adjoin the digits to the end aback you pop them from the assemblage as described. 3 3. In the third task, you will address two functions that will be able to array a stack. Aboriginal of all, you should address a simpler adjustment that, accustomed an already sorted assemblage as input, and an account of the aforementioned blazon as the assemblage type, the account should be amid into the actual position on the sorted assemblage to accumulate it sorted. For example, the endless will be sorted in ascendance order, area the account at the basal of the assemblage is the aboriginal value, and the account at the top is the largest, like this: top: 8 7 5 3 1 :bottom If we alarm the action to admit a 4 into this sorted stack, the aftereffect should be: top: 8 7 5 4 3 1 Your action should be alleged insertItemOnSortedStack(). This action takes an account as its rst parameter, and a advertence to a Assemblage as its additional parameter. You should actualize and use addition acting assemblage in your action in adjustment to accmplish the task. The pseudo-code to achieve this admittance is almost simple: accustomed inputStack and actualize temporaryStack for this algorithm while top of inputStack > account we appetite to admit do pop topItem from inputStack advance topItem assimilate the temporaryStack done at this point, items on inputStack are <= to the account we appetite to admit so advance account assimilate inputStack now put items aback from temporaryStack to aboriginal inputStack while temporaryStack is not abandoned do pop topItem from temporaryStack advance topItem assimilate the inputStack done 4 The tests accustomed for the admit action use an AStack (a assemblage of integers) for the tests. You can originally actualize your action to use a Assemblage & as its additional ascribe parameter. It is important that the assemblage be a advertence constant here. Additionally apprehension that instead of allegorical an AStack &, we specify the abstruse abject chic Assemblage &. This is to authenticate the ability of application basic classes and chic abstractions. If you specify the abject class, you can canyon an AStack or an LStack or any chic that is acquired from the abject Assemblage class, as continued as that chic accouterments all of the basic functions of the abstruse Assemblage interface. Once you accept your action alive for Assemblage &, templatize your function. We accomplished creating action templates in a antecedent assignment. Actuality it should be almost simple, you artlessly charge to add the arrangement  before the function, and change the  to  to templatize. Once you do this, you action should still appointment and canyon the tests application an  type. Once you accept your insertItemOnSortedStack() arrangement action working, it is alike easier to use this action to actualize a sortStack() function. We could apparatus this action afresh application a acting stack, but for this fourth and nal action I appetite you instead to actualize a recursive function. A recursive action in this case is activity to appointment in about the aforementioned way, but we will be application the OS/system action alarm assemblage around to achieve the algorithm, rather than absolutely creating and application our own acting stack. Actualize a action alleged sortStack(). This action should booty a Assemblage & (a advertence to a Assemblage of  types) as its alone parameters. You will after templatize this action as well, but all of the tests of sortStack() use endless of strings, so get it alive rst for strings, afresh try and templatize the function. This is a abandoned funciton, it doesn't acknowledgment a result, but it around causes the assemblage it is accustomed to become sorted. The function, as the name implies, will booty an amateurish stack, and will array them in the aforementioned adjustment we acclimated previously, e.g. in ascendance adjustment with the aboriginal account at the basal of the stack, and the better at the top. The pseudo-code to achieve this application a recursize algorithm is as follows: 5 accustomed inputStack as an ascribe constant # the abject case if inputStack is empty, do annihilation (return) # the accepted case booty top account from inputStack and save it in a bounded capricious alarm sortStack(inputStack) recursively on this now abate assemblage # on return, the assemblage should be sorted, so insertItemOnSortedStack(my account I popped, inputStack) Once you accept it alive for  type stacks, additionally templatize your sortStack() function, so that it will absolutely appointment to array a Assemblage of any type. In this appointment you will alone be accustomed 2 les, an assg-10-tests.cpp le with a capital action and assemblage tests of the functions you are to write. You will additionally use the Stack.hpp attack le that was developed and apparent in the videos for chic this week. You should not accept to add or change any cipher in Stack.hpp. You aloof charge to use the Assemblage chic to apparatus your code/functions for this assignment. As usual, the tests accept been commented out. I acerb advance you apparatus the functions one at a time, in the adjustment declared above, and uncomment anniversary analysis 1 at a time to analysis your appointment incrementally. 

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